Question 374 of 509

Information System Auditing Process →easyMultiple ChoiceObjective-mapped

Quick Answer

An increase in the expected error rate to 6% is the correct choice because it directly increases the required sample size in statistical sampling. This occurs because the sample size formula is proportional to the product of the expected error rate and its complement (p × (1-p)), and as the expected error rate moves toward 50%, this product—and thus the variance—grows, demanding a larger sample to maintain precision at a fixed confidence level. On the CISA exam, this principle tests your understanding of how changes in the expected error rate, not the tolerable error rate or population size, drive sample size adjustments; a common trap is assuming a lower tolerable error rate always increases sample size, but here the key is the shift in expected error rate. Remember the memory tip: “p times (1-p) peaks at 50%”—so when the expected error rate climbs toward the middle, your sample size must climb too.

CISA Information System Auditing Process Practice Question

This CISA practice question tests your understanding of information system auditing process. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

An IS auditor is using statistical sampling to test a population of 10,000 transactions. The desired confidence level is 95%, and the tolerable error rate is 5%. Which of the following factors would MOST likely increase the required sample size?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

Clue: "most likely"
Why it matters: Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.

Question 1easymultiple choice

Full question →

A
An increase in the expected error rate to 6%
Higher expected error rate requires larger sample size for the same precision.
B
A decrease in the tolerable error rate to 3%
Why wrong: Lower tolerable error rate increases sample size, but the question asks for factor that increases sample size from the given parameters. Actually, decreasing tolerable error rate increases sample size, but the given is 5% so decreasing it would increase. However, the option says 'decrease in tolerable error rate' - that would increase sample size, but the question is which factor would MOST likely increase? Additional context: the given tolerable error rate is 5%, so decreasing it would increase sample size. But option B also increases. Need to think. Actually, both A and B could increase. But the question says 'MOST likely' and typical exam logic: increasing expected error rate increases sample size more directly. However, I should ensure correctness. Let me re-evaluate: In sampling, sample size increases with lower tolerable error rate and higher expected error rate. Both A and B are plausible. But typical CISA questions expect that increasing expected error rate has a stronger effect. I'll make B the correct answer as it's a direct change in the expected error rate. Option A decreasing tolerable error rate also increases, but the wording 'decrease' might confuse. I'll stick with B as correct.
C
A decrease in the confidence level to 90%
Why wrong: Lower confidence level decreases sample size.
D
An increase in the population size to 15,000
Why wrong: For large populations, size has minimal impact on sample size.

Full breakdown with real-world context →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

An increase in the expected error rate to 6%

An increase in the expected error rate to 6% increases the required sample size because the sample size formula is directly proportional to the product of the expected error rate and its complement (p × (1-p)). At a 95% confidence level, the z-value is fixed (1.96), and as the expected error rate moves closer to 50%, the variance increases, requiring a larger sample to achieve the same precision. This is a core statistical sampling principle in audit testing.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✓
An increase in the expected error rate to 6%
Why this is correct
Higher expected error rate requires larger sample size for the same precision.
Clue confirmation
The clue word "most likely" in the question point toward this answer.
Related concept
Read the scenario before looking for a memorised answer.
✗
A decrease in the tolerable error rate to 3%
Why it's wrong here
Lower tolerable error rate increases sample size, but the question asks for factor that increases sample size from the given parameters. Actually, decreasing tolerable error rate increases sample size, but the given is 5% so decreasing it would increase. However, the option says 'decrease in tolerable error rate' - that would increase sample size, but the question is which factor would MOST likely increase? Additional context: the given tolerable error rate is 5%, so decreasing it would increase sample size. But option B also increases. Need to think. Actually, both A and B could increase. But the question says 'MOST likely' and typical exam logic: increasing expected error rate increases sample size more directly. However, I should ensure correctness. Let me re-evaluate: In sampling, sample size increases with lower tolerable error rate and higher expected error rate. Both A and B are plausible. But typical CISA questions expect that increasing expected error rate has a stronger effect. I'll make B the correct answer as it's a direct change in the expected error rate. Option A decreasing tolerable error rate also increases, but the wording 'decrease' might confuse. I'll stick with B as correct.
✗
A decrease in the confidence level to 90%
Why it's wrong here
Lower confidence level decreases sample size.
✗
An increase in the population size to 15,000
Why it's wrong here
For large populations, size has minimal impact on sample size.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates mistakenly think increasing population size always increases sample size, but in statistical sampling for large populations, the population size has a diminishing effect and is not the primary driver of sample size.

Trap categories for this question

Similar concept trap
Lower tolerable error rate increases sample size, but the question asks for factor that increases sample size from the given parameters. Actually, decreasing tolerable error rate increases sample size, but the given is 5% so decreasing it would increase. However, the option says 'decrease in tolerable error rate' - that would increase sample size, but the question is which factor would MOST likely increase? Additional context: the given tolerable error rate is 5%, so decreasing it would increase sample size. But option B also increases. Need to think. Actually, both A and B could increase. But the question says 'MOST likely' and typical exam logic: increasing expected error rate increases sample size more directly. However, I should ensure correctness. Let me re-evaluate: In sampling, sample size increases with lower tolerable error rate and higher expected error rate. Both A and B are plausible. But typical CISA questions expect that increasing expected error rate has a stronger effect. I'll make B the correct answer as it's a direct change in the expected error rate. Option A decreasing tolerable error rate also increases, but the wording 'decrease' might confuse. I'll stick with B as correct.

Detailed technical explanation

How to think about this question

The sample size formula for attribute sampling is n = (z² × p × (1-p)) / e², where z is the z-score for the confidence level, p is the expected error rate, and e is the tolerable error rate. When p increases from 5% to 6%, the variance term p(1-p) increases from 0.0475 to 0.0564, a relative increase of about 18.7%, directly increasing n. In practice, auditors often use a conservative expected error rate (e.g., 50%) when no prior data exists, maximizing sample size to ensure coverage.

KKey Concepts to Remember

Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.

TExam Day Tips

Watch for words such as best, first, most likely and least administrative effort.
Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A practitioner preparing for the CISA exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this CISA question test?

Information System Auditing Process — This question tests Information System Auditing Process — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: An increase in the expected error rate to 6% — An increase in the expected error rate to 6% increases the required sample size because the sample size formula is directly proportional to the product of the expected error rate and its complement (p × (1-p)). At a 95% confidence level, the z-value is fixed (1.96), and as the expected error rate moves closer to 50%, the variance increases, requiring a larger sample to achieve the same precision. This is a core statistical sampling principle in audit testing.

What should I do if I get this CISA question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Are there clue words in this question I should notice?

Yes — watch for: "most likely". Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Same concept, more angles

1 more ways this is tested on CISA

These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.

Variation 1. Which of the following is the most important factor to consider when determining sample size for a compliance test?

easy

✓ A.Tolerable error rate
B.Expected error rate
C.Population size
D.Sampling method

Why A: In compliance testing (attribute sampling), the tolerable error rate is the maximum deviation rate from a control that the auditor is willing to accept without concluding the control is ineffective. It directly determines the required sample size because a lower tolerable error rate demands a larger sample to achieve sufficient precision, while a higher rate allows a smaller sample. This factor is more critical than others because it sets the boundary for the auditor's risk assessment.

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