PCEP Computer Programming and Python Fundamentals Practice Test 8 — 15 Questions

Question 1

Refer to the exhibit. A developer runs this code. What is printed?

Accepted Answer

Running in normal mode. config.get('debug', False) returns False because the key 'debug' exists with value False. The condition is False, so the else branch prints 'Running in normal mode'.

Answer

Error

Answer

True

Answer

Debug mode active

Question 2

Which TWO of the following are valid Python variable names?

Accepted Answer

my_var2. Valid variable names can start with underscore or letter, and contain letters, digits, underscores. Keywords are not allowed.

Answer

2nd_var

Answer

my-var

Answer

for

Question 3

Which THREE of the following are built-in Python data types?

Accepted Answer

tuple. list, tuple, and set are built-in data types. array is from the array module, and dictionary is not a type name (the type is dict).

Answer

array

Answer

dictionary

Question 4

Which TWO statements correctly describe Python's dynamic typing?

Accepted Answer

The interpreter infers the type from the assigned value.. Dynamic typing means variable types are inferred at runtime and can change. Types are not checked at compile time.

Answer

Variable types must be declared before use.

Answer

Python checks types only at compile time.

Answer

A variable's type is fixed once assigned.

Question 5

Which of the following variable names is valid in Python?

Accepted Answer

_private. Option C is correct because variable names can start with an underscore. Option A is wrong because it starts with a digit. Option B is wrong because 'my-var' contains a hyphen. Option D is wrong because 'class' is a reserved keyword.

Answer

1st_value

Answer

class

Answer

my-var

Question 6

What is the result of the following expression? 3 + 4 * 2 ** 3 // 5

Accepted Answer

9. Option B is correct following operator precedence: ** first (2**3=8), then * (4*8=32), then // (32//5=6), then + (3+6=9). Options A, C, D reflect different precedence errors.

Answer

7

Answer

6

Answer

11

Question 7

Given the code: my_list = [1, 2, 3, 4, 5]. What is the output of print(my_list[-3:-1])?

Accepted Answer

[3, 4]. Option B is correct because slicing with negative indices: -3 is index 2 (value 3), -1 is index 4 (value 5) but stop is exclusive, so elements at indices 2 and 3 are included, i.e., [3,4]. Option A gives [2,3] which is slice from -4 to -2. Option C is [3,4,5] which is -3:. Option D is [4,5] which is -2:.

Answer

[4, 5]

Answer

[2, 3]

Answer

[3, 4, 5]

Question 8

What does the following code print? text = 'Hello World'; print(text.replace('o', '0').upper())

Accepted Answer

HELL0 W0RLD. Option A is correct: replace 'o' with '0' gives 'Hell0 W0rld', then .upper() converts to uppercase: 'HELL0 W0RLD'. Option B does not replace o. Option C does not uppercase. Option D is lowercase with replace.

Answer

hell0 w0rld

Answer

HELLO WORLD

Answer

Hell0 W0rld

Question 9

Which of the following is a floating-point literal?

Accepted Answer

3.14. Option B is correct because '3.14' is a float literal. Option A is an integer. Option C is a complex number. Option D is a string.

Answer

'3.14'

Answer

42

Answer

1+2j

Question 10

What is the output of the following code? try: print(1/0); except ZeroDivisionError: print('error'); finally: print('done')

Accepted Answer

error
done. Option C is correct: division by zero raises ZeroDivisionError, caught by except, prints 'error', then finally block always runs, prints 'done'. Option A misses the error message. Option B misses finally. Option D reverses order.

Answer

error

Answer

done
error

Answer

1/0
done

Question 11

Which keyword is used to define a function in Python?

Accepted Answer

def. Option A is correct: 'def' defines a function. Option B 'function' is not a keyword. Option C 'define' is not a keyword. Option D 'func' is not a keyword.

Answer

func

Answer

function

Answer

define

Question 12

What does the following code output? for i in range(3): if i == 1: continue; print(i, end=' ')

Accepted Answer

0 2. Option B is correct: range(3) gives 0,1,2. When i==1, continue skips the print, so prints 0 and 2. Option A prints all. Option C prints only 1. Option D prints only 0.

Answer

1

Answer

0 1 2

Answer

0

Question 13

Consider the code: x = 10; def func(): x = 5; print(x); func(); print(x). What is the output?

Accepted Answer

5
10. Option D is correct: inside function, local x=5 shadows global x=10, so prints 5; after function, global x is still 10, so prints 10. Option A would happen if global x changed. Option B if both printed 5. Option C if both printed 10.

Answer

5
5

Answer

10
10

Answer

10
5

Question 14

Which TWO of the following are immutable data types in Python?

Accepted Answer

str. Correct options are B and D: integers are immutable, tuples are immutable. Lists and dictionaries are mutable. Strings are immutable but not in options? Wait: options A-E: A) list, B) int, C) dict, D) tuple, E) set? Actually I need to provide 5 options. Let me define: A) list, B) dict, C) tuple, D) str, E) int. That covers. Actually typical PCEP: int, float, bool, str, tuple are immutable; list, dict, set mutable. So pick two immutables: tuple and int? Or str and int? I'll do B (tuple) and D (str). But careful: which TWO? Let's set options: A) list, B) tuple, C) dict, D) str, E) int. Correct: B and D (tuple and str) or B and E? Actually str is immutable, int is immutable. Both are correct. I need exactly TWO correct. I'll choose B and D as correct, but then E is also correct? That would be three. So better to only have two correct. Let's pick options where only two are immutable. Common immutable: int, float, bool, str, tuple, bytes, frozenset. So I'll set: A) list, B) tuple, C) dict, D) set, E) str. Then immutables: tuple and str. So correct: B and E. That works. Explanation: B (tuple) and E (str) are immutable; others mutable.

Answer

set

Answer

dict

Answer

list

Question 15

Which TWO of the following code snippets will produce the output 'True'? (Assume all variables are defined appropriately.)

Accepted Answer

print(3.0 == int(3.0)). Correct options are B and D. B: 'is' checks identity, and a and b point to same small integer due to caching. D: 3.0 == 3 returns True due to type coercion. A: 'is' with different float objects returns False. C: 1 <= 2 <= 3 is chained comparison: 1<=2 and 2<=3 -> True and True -> True, but that's actually True? Wait 1 <= 2 <= 3 is True. But we need TWO correct. Let me recalc: A) x=2.0; y=2.0; print(x is y) -> may be False because floats are not small ints; typically False. B) a=5; b=5; print(a is b) -> True due to integer caching. C) print(1 <= 2 <= 3) -> True. D) print(3.0 == 3) -> True. E) print('ab' == 'ba') -> False. So three options give True? That's three correct, but we need exactly two. So adjust: make C False? For example, print(1 <= 2 <= 1) -> False. Or change to something else. Let me redesign: A) print(2.0 is 2.0) -> probably False (no small float cache). B) a=256; b=256; print(a is b) -> True (integers -5 to 256 cached). C) print(1 < 2 < 3) -> True. D) print(3.0 == int(3.0)) -> True. E) print('abc' == 'abc') -> True. That's three. So to have exactly two, we need to make one of these false. For C, change to 1 < 2 < 1 -> False. For D, change to 3.0 == 3 -> still True. For E, change to 'ab' == 'ba' -> False. So then only B and D are True. That works. But careful: int(3.0) is 3, so True. So final snippet: A) x=2.0; y=2.0; print(x is y) -> False. B) a=256; b=256; print(a is b) -> True. C) print(1 < 2 < 1) -> False. D) print(3.0 == int(3.0)) -> True. E) print('ab' == 'ba') -> False. Thus correct: B and D.

Answer

x=2.0; y=2.0; print(x is y)

Answer

print(1 < 2 < 1)

Answer

print('ab' == 'ba')

PCEP Computer Programming and Python Fundamentals Practice Test 8 — 15 Questions

Exhibit

PCEP Computer Programming and Python Fundamentals Practice Test 8 — 15 Questions

Exhibit